public string FirstName { get; set; }
public string LastName { get; set; }
public int Salary { get; set; }
public override string ToString() {
return FirstName + ', ' + LastName + ' $' + Salary;
}
public int CompareTo(Employee emp) {
return this.FirstName.CompareTo(emp.FirstName);
}
}
You can now sort the Employee
objects using the default, or specify the SalarySorter
property:
employees.Sort(); //---sort using FirstName (default)---
employees.Sort(Employee.SalarySorter); //---sort using Salary---
To allow the Employee
objects to be sorted using the LastName
property, you could define another class (say LastNameComparer
) that implements the IComparer<T>
interface and then declare the SalarySorter
static property, like this:
public class Employee : IComparable<Employee> {
private class SalaryComparer : IComparer<Employee> {
public int Compare(Employee e1, Employee e2) {
if (e1.Salary < e2.Salary) return -1;
else if (e1.Salary == e2.Salary) return 0;
else return 1;
}
}
public static IComparer<Employee> SalarySorter {
get { return new SalaryComparer(); }
}
public string FirstName { get; set; }
public string LastName { get; set; }
public int Salary { get; set; }
public override string ToString() {
return FirstName + ', ' + LastName + ' $' + Salary;
}
public int CompareTo(Employee emp) {
return this.FirstName.CompareTo(emp.FirstName);
}
}
You can now sort by LastName
using the LastNameSorter
property:
employees.Sort(Employee.LastNameSorter); //---sort using LastName---
Dictionary
Most of you are familiar with the termDictionary
class (the generic equivalent is Dictionary<T,V>
).
The following shows how you can create a new Dictionary
object with type int to be used for the key and type String
to be used for the values:
Dictionary<int, string> employees = new Dictionary<int, string>();
To add items into a Dictionary
object, use the Add()
method:
employees.Add(1001, 'Margaret Anderson');
employees.Add(1002, 'Howard Mark');
employees.Add(1003, 'John Smith');
employees.Add(1004, 'Brian Will');
Trying to add a key that already exists in the object produces an ArgumentException error:
//---ArgumentException; duplicate key---
employees.Add(1004, 'Sculley Lawrence');
A safer way is to use the ContainsKey()
method to check if the key exists before adding the new key:
if (!employees.ContainsKey(1005)) {
employees.Add(1005, 'Sculley Lawrence');
}
While having duplicate keys is not acceptable, you can have different keys with the same value:
employees.Add(1006, 'Sculley Lawrence'); //---duplicate value is OK---
To retrieve items from the Dictionary object, simply specify the key:
Console.WriteLine(employees[1002].ToString()); //---Howard Mark---
When retrieving items from a Dictionary
object, be certain that the key you specify is valid or you encounter a KeyNotFoundException
error:
try {
//---KeyNotFoundException---
Console.WriteLine(employees[1005].ToString());
} catch (KeyNotFoundException ex) {
Console.WriteLine(ex.Message);
}
Rather than catching an exception when the specified key is not found, it's more efficient to use the TryGetValue()
method:
string Emp_Name;
if (employees.TryGetValue(1005, out Emp_Name))
Console.WriteLine(Emp_Name);
TryGetValue()
takes in a key for the Dictionary
object as well as an out parameter that will contain the associated value for the specified key. If the key specified does not exist in the Dictionary
object, the out parameter (Emp_Name
, in this case) contains the